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is anyone on this board competent in calculus ?

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K A I N:
Calculus II will kill you if you having problems with this... ;D

It's scary how I forgot all this shit  :-\

http://www.mathematicshelpcentral.com/lecture_notes/calculus_1.htm


btw fuck geometry

coola:
yeah nibs, i was wondering wtf you changed the 3 to a 1 before... ima go eat some soup then put down on paper your workings... the solution is different in the text  :-\

coola:

--- Quote from: Doggie KAIN on April 28, 2006, 11:23:23 AM ---Calculus II will kill you if you having problems with this... ;D

It's scary how I forgot all this shit  :-\

http://www.mathematicshelpcentral.com/lecture_notes/calculus_1.htm


btw fuck geometry

--- End quote ---

yeah this is only my first year... its basic stuff and i'm struggling  >:( might need a tutor next year.. hot blonde will do  ;D

props for the web-site !

coola:
heres the solution... i'm hittin the sack, too much for one night..

[ 3((y^2) + 1)((y^2) - 2x + 1) ] / [ ((y^2) + 1)^2 - 6(x^2)y ]

fuck knows hot to get that  :'(

nibs:
i factored wrong:

3x^2((y^2)+1)^-1 + y = 3x + 1

6x((y^2)+1)^-1 - 3x^2((y^2)+1)^-2(2ydy/dx) + dy/dx = 3

6x((y^2)+1)^-1 - 6x^2(ydy/dx)((y^2)+1)^-2 + dy/dx = 3

6x((y^2)+1)^-1 + (1 - 6yx^2((y^2)+1)^-2)dy/dx = 3

6x((y^2)+1)^-1 - 3 = (6yx^2((y^2)+1)^-2 - 1)dy/dx

(6x / ((y^2) + 1) - 3) / (6yx^2((y^2)+1)^-2 - 1)  =  dy/dx

then they simplified this further:

(6x / ((y^2) + 1) - 3) / (6yx^2((y^2)+1)^-2 - 1)  =  dy/dx

(6x((y^2)+1)^2 / ((y^2) + 1) - 3((y^2)+1)^2) / ( 6yx^2 - ((y^2)+1)^2)  =  dy/dx

(6x((y^2)+1) - 3((y^2)+1)^2) / ( 6yx^2 - ((y^2)+1)^2)  =  dy/dx

(6x((y^2)+1) - 3((y^2)+1)((y^2)+1)) / ( 6yx^2 - ((y^2)+1)^2)  =  dy/dx

[ 3((y^2)+1)(2x - (y^2) + 1) ] / [  6yx^2 - ((y^2)+1)^2 ]  =  dy/dx

factoring out the minus sign

[ 3((y^2)+1)((y^2) - 2x + 1) ] / [ ((y^2)+1)^2 - 6y(x^2) ]  =  dy/dx

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