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i need more help in calculus !!

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coola:
 :'( i have exams in a week, and i suck... i'm trying to cram 4 weeks worth of work...

anyway, i'm struggling with area under curve, only when the boundaries are the y-axis... i cant re-write the equation to suit the x-axis and work it out from there... thats just my lack of high-school knowledge i know... but these calculus books dont teach shit.

y=X^(1/2) , x=0, y=1, y=3

it's all too easy when the boundaries are the x-axis, but y just shits me... please help !!!

coola:
ivee sussed out you just substitute the y=3 or y=1, and get the values of x through algebra... but how do i re-make the equation into y= ???

damn this late night study is killing me  :-X

coola:
so i did it, but using unorthodox methods...

i got the area for the boundaries x=1 and x=9, (the area under the curve), then i subtracted it from the area of the square (luckily in this problem it was a strait line boundary), the remaining shizz is the area over the curve..

but i wont know how to do it for quadratics  :-\

QuietTruth:
LMAO...Holy shit I couldn't solve that if my life depended on it :-\

coola:

--- Quote from: QuietTruth on June 06, 2006, 12:15:31 PM ---LMAO...Holy shit I couldn't solve that if my life depended on it :-\

--- End quote ---

i bet you could if you were studying calculus  ;) it's all just formula bullshit, i can do it, i just leave everything to the last minute... i am seriously cramming like crazy... i have 6 days to learn 3 weeks worth of syllabus, then revise 8 weeks worth of work... and i need a minimum of 60% in this exam to pass the unit... THE PRESSURE IS ON !!! BOO YAA !  8)

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