West Coast Connection Forum
Lifestyle => Tha G-Spot => Topic started by: boycriedwolf619 on October 05, 2007, 06:05:27 PM
-
Wondering if any of you guys can be of assistance to me.
I have to integrate 6x/(x^3-8) NOT DERIVATION!
I figured that you have to break down the denominator, so I did so by the difference of cubes formula and got : (x^3-2^3)(x^2+2x+4)
SO no the problem is 6x/(x^3-2^3)(x^2+2x+4)
Then the integration problem is A/(x-2) + Bx+C (x^2-2x-4) After getting the common denominator, I solved for the coefficients and got A=1 , B=-1, C=2
So then the integration problem is dx/(x-2) + (-1x+2)/(x^2+2x+4) dx . The first integration is ln | x-2 |
The second one, I figure splitting it into two integrations.
So, it becomes the integration of -1x/(x^2+2x+4)dx + the integration of 2/(x^2+2x+4). This integration 2/(x^2+2x+4) I got ln | x^2+2x+4 |. Im having problems integrating this part -1x/(x^2+2x+4)dx. Anybody got any clues suggestion or hints much aprreciated!
-
damn doggie
u tryn to be a rocket scientist?
-
damn doggie
u tryn to be a rocket scientist?
LMAO!!! nah I was tryin to do my thing in computer science but not really feeling it any more. Thinking about mathematics but i dunno what I want to do. but i know it would be in the field of math / science / tech
-
you crazy man
i failed algebra one to many times
-
you crazy man
i failed algebra one to many times
LOl well i failed this course calculus 2 first time and retaken it.
-
you crazy man
i failed algebra one to many times
LOl well i failed this course calculus 2 first time and retaken it.
nah
i failed algebra 2 once, then i failed it twice, then i failed it 3 times and then i failed it for the fourth time
shit is too hard for my genius brain
-
Somehow, I think you went too far. It's been awhile since the last time I did integration but the answer should have been simpler than what you came up with